Sun System Handbook - ISO 3.4 June 2011 Internal/Partner Edition | |||
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Solution Type Technical Instruction Sure Solution 1020837.1 : How to determine how a RAID 1 Virtual Disk is built in a Storage[TM] 2500 and 6000 Array
PreviouslyPublishedAs 265729
Applies to:Sun Storage 2530 Array - Version: Not Applicable to Not Applicable - Release: N/A to N/ASun Storage 2540 Array - Version: Not Applicable to Not Applicable [Release: N/A to N/A] Sun Storage 6140 Array Sun Storage 6580 Array - Version: Not Applicable to Not Applicable [Release: N/A to N/A] Sun Storage 6540 Array All Platforms GoalThe intent of this document is to explain how RAID 1 are built in the array and how to determine the mirror pairs.In a RAID 1+0 Virtual Disk (vdisk) the disks are mirrored using the following algorithm: Data drive = X Mirrored drive = N/2+X where: - N is the total number of physical disks. - X goes from 1 to N/2 For example, if you have six physical disks (1, 2, 3, 4, 5, 6) the mirror pairs are: Mirrored disks: For disk 1: 6/2+1= disk 4 For disk 2: 6/2+2= disk 5 For disk 3: 6/2+3= disk 6 The first disk of the first half is mirrored to the first disk of the second half, the second disk of the first half is mirrored to the second disk of the second half, etc, up to the last disk of the first half is mirrored to the last disk of the second half. Solution1) Collect a supportdata.Reference <Document 1002514.1> Collecting Support Data for Arrays Using Sun StorageTek[TM] Common Array Manager. Reference <Document 1014074.1> Collecting Support Data for Arrays Using Sun StorageTek[TM] SANtricity Storage Manager. 2) Extract the vdisk details.
Example: Based on the above output, the mirror pairs are: Tray.85.Drive.7 is mirrored with Tray.85.Drive.15. Tray.85.Drive.10 is mirrored with Tray.85.Drive.11. Attachments This solution has no attachment |
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